if a+2b+3c=0 prove a3 +8b3+27c3=18abc
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Answered by
48
if a + 2b + 3c = 0
then a3 + 8b3 + 27c3 = 18abc
if a-2b-3c=0 then ........changing the signs
a3 - 8b3 - 27c3 = 18abc
i hope it helps u
then a3 + 8b3 + 27c3 = 18abc
if a-2b-3c=0 then ........changing the signs
a3 - 8b3 - 27c3 = 18abc
i hope it helps u
Answered by
145
Hi ,
a + 2b + 3c = 0 ---( 1 )
a + 2b = - 3c ---( 2 )
( a + 2b )³ = ( - 3c )³
a³ + ( 2b )³ + 3 × a × 2b ( a + 2b ) = - 27c³
a³ + 8b³ + 27c³ + 6ab × ( - 3c ) = 0
[from ( 2 ) ]
a³ + 8b³ + 27c³ - 18abc = 0
a³ + 8b³ + 27c³ = 18abc
Hence proved .
I hope this helps you.
: )
a + 2b + 3c = 0 ---( 1 )
a + 2b = - 3c ---( 2 )
( a + 2b )³ = ( - 3c )³
a³ + ( 2b )³ + 3 × a × 2b ( a + 2b ) = - 27c³
a³ + 8b³ + 27c³ + 6ab × ( - 3c ) = 0
[from ( 2 ) ]
a³ + 8b³ + 27c³ - 18abc = 0
a³ + 8b³ + 27c³ = 18abc
Hence proved .
I hope this helps you.
: )
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