if a+2b+3c = 0 prove that a3+8b3+27c3 = 18abc
Answers
Answered by
5
Answer:
When a+b+c=0; a^3+b^3+C^3=3ABC
Step-by-step explanation:
This can be used to prove that statement
Answered by
13
Answer:
If x+y+z is zero
then x³+y³+z³=3xyz
use the same identity
a+2b+3c=0
so,
3(a)(2b)(3c) =a³+(2b)³+(3c)³
18abc=a³+8b³+27c³
proved
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