Math, asked by NayanJadhav, 10 months ago

if a+2b+3c = 0 prove that a3+8b3+27c3 = 18abc​

Answers

Answered by phonix1
5

Answer:

When a+b+c=0; a^3+b^3+C^3=3ABC

Step-by-step explanation:

This can be used to prove that statement

Answered by NakulMudgal4433
13

Answer:

If x+y+z is zero

then x³+y³+z³=3xyz

use the same identity

a+2b+3c=0

so,

3(a)(2b)(3c) =a³+(2b)³+(3c)³

18abc=a³+8b³+27c³

proved

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