Question

If a + 2b + 3c = 0, show that a³ + 8b³ + 27 c³= 18 abc.
[Hint. x + y + z = 0 = x3 + y3 + z3 = 3xyz.]​

Answer 1

Answer:

A+2b+3c=0 then

a+2b=-3c

(a+2b)3=(-3c)3 (By cubing)

a3+(2b)3+3(a)(2b)(a+2b) = -27c3

a3+8b3+6ab (-3c) = -27c3 [a+2b=-3c]

a3+8b3-18abc = -27c3

a3+8b3+27c3 = 18abc

Step-by-step explanation:

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