Question

if a+2b+3c=0 then show that a³+8b³+27c³= 18abc​

Answer 1

Answer:

it's easy answer ........................

Answer 2

Answer:

2a+3b+c=0

2a+2b=-c

cubing both sides we get

(2a+3b squ3)=(-c) squ3

8a squ 3+27b squ3+18ab(2a+3b)=-c squ 3

8a squ 3+27b squ 3+18ab(-c)=-c squ 3

since 2a+3b=-c

8a squ3+27b squ3-18abc=--c squ3

8a squ3+27b squ3+c squ3=18abc