if a+2b=4c, then find the value of a³+8b³-64c³+24abc
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Answer:
a + 2b = 4c
( a + 2b )³ = ( 4c )³
a³ + 8b³ + 6a²b + 12ab² = 64c³
a³ + 8b³ - 64c³ = - ( 6a²b + 12ab² )
so ,
24abc - 6a²b - 12ab²
6ab [ 4c - a - 2b ]
6ab ( 0 )
0
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