Math, asked by Angel12340, 8 months ago

If
a + 2b = 5; then show that :
a^3 + 8b^3 + 30ab = 125​

Answers

Answered by vinayvsnaidup6t7c5
5
I hope that you got your required answer
Attachments:
Answered by Anonymous
0

Answer:

hiii

your answer is here !

Step-by-step explanation:

Hope u like my process,

Hope u like my process,____________________

Hope u like my process,____________________Here we go,

Hope u like my process,____________________Here we go,Formula to be used :

Hope u like my process,____________________Here we go,Formula to be used :———————————

Hope u like my process,____________________Here we go,Formula to be used :———————————(x + y) ³ = x³ + y³ + 3xy(x+y).

Hope u like my process,____________________Here we go,Formula to be used :———————————(x + y) ³ = x³ + y³ + 3xy(x+y).----------------------------------------

Hope u like my process,____________________Here we go,Formula to be used :———————————(x + y) ³ = x³ + y³ + 3xy(x+y).----------------------------------------(a +2b) = 5

Hope u like my process,____________________Here we go,Formula to be used :———————————(x + y) ³ = x³ + y³ + 3xy(x+y).----------------------------------------(a +2b) = 5Cubing both sides we get,

Hope u like my process,____________________Here we go,Formula to be used :———————————(x + y) ³ = x³ + y³ + 3xy(x+y).----------------------------------------(a +2b) = 5Cubing both sides we get,¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

Hope u like my process,____________________Here we go,Formula to be used :———————————(x + y) ³ = x³ + y³ + 3xy(x+y).----------------------------------------(a +2b) = 5Cubing both sides we get,¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(a +2b) ³ = 5³

Hope u like my process,____________________Here we go,Formula to be used :———————————(x + y) ³ = x³ + y³ + 3xy(x+y).----------------------------------------(a +2b) = 5Cubing both sides we get,¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(a +2b) ³ = 5³or, (a) ³ + (2b)³ + 3a.2b(a+2b) =125

Hope u like my process,____________________Here we go,Formula to be used :———————————(x + y) ³ = x³ + y³ + 3xy(x+y).----------------------------------------(a +2b) = 5Cubing both sides we get,¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(a +2b) ³ = 5³or, (a) ³ + (2b)³ + 3a.2b(a+2b) =125or, a³ + 8b³ + 6ab×5 =125_( since a+2b=5)_

Hope u like my process,____________________Here we go,Formula to be used :———————————(x + y) ³ = x³ + y³ + 3xy(x+y).----------------------------------------(a +2b) = 5Cubing both sides we get,¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(a +2b) ³ = 5³or, (a) ³ + (2b)³ + 3a.2b(a+2b) =125or, a³ + 8b³ + 6ab×5 =125_( since a+2b=5)_or, a³ + 8b³ +30ab = 125 __(proved)__

Hope u like my process,____________________Here we go,Formula to be used :———————————(x + y) ³ = x³ + y³ + 3xy(x+y).----------------------------------------(a +2b) = 5Cubing both sides we get,¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(a +2b) ³ = 5³or, (a) ³ + (2b)³ + 3a.2b(a+2b) =125or, a³ + 8b³ + 6ab×5 =125_( since a+2b=5)_or, a³ + 8b³ +30ab = 125 __(proved)___-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_

Hope u like my process,____________________Here we go,Formula to be used :———————————(x + y) ³ = x³ + y³ + 3xy(x+y).----------------------------------------(a +2b) = 5Cubing both sides we get,¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(a +2b) ³ = 5³or, (a) ³ + (2b)³ + 3a.2b(a+2b) =125or, a³ + 8b³ + 6ab×5 =125_( since a+2b=5)_or, a³ + 8b³ +30ab = 125 __(proved)___-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_Hope u got it.

Hope u like my process,____________________Here we go,Formula to be used :———————————(x + y) ³ = x³ + y³ + 3xy(x+y).----------------------------------------(a +2b) = 5Cubing both sides we get,¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(a +2b) ³ = 5³or, (a) ³ + (2b)³ + 3a.2b(a+2b) =125or, a³ + 8b³ + 6ab×5 =125_( since a+2b=5)_or, a³ + 8b³ +30ab = 125 __(proved)___-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_Hope u got it. Proud to help you.

follow me !

Similar questions