if a 2b and c are in A.P prove that 4(4b2_ac)=(a_c)2
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Step-by-step explanation:
Given a,2b,c are in A.P
so,Arithmetic mean is
2b=(a+c)/2
4b=a+c....eq1
4(4b^2-ac)=16b^2-4ac
=(a+c)^2-4ac
=a^2+c^2+2ac-4ac
=a^2+c^2-2ac
=(a-c)^2
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