Question

If A= (2i+2j+2k) and B= (3i+4j). Determine the vector having same magnitude as B and parallel to A.​

Answer 1

Answer:

this an example sum

Explanation:

Correct option is

D

15

i

^

+20

j

^

∣B∣=

7

2

+(24)

2

=

625

=25

Unit vector in the direction of A will be A=

5

3

i

^

+4

j

^

So required vector =25(

5

3

i

^

+4

j

^

)=15

i

^

+20

j

^

Answer 2

Answer:

10i + 10j + 10k/2√2

Explanation:

A= 2i + 2j + 2k

B = 3i + 4j

Let the vector having same magnitude as B and parallel to A be C

C = |B| x  ( magnitude x unit vector )

a unit vector is parallel to Ā

|B|=√(3)^2 + (4)^2 = 5

unit vector= Ā/|A|

|A|=✓(2)^2 +(2)^2 +(2)^2 =. 2√2

unit vector (Â) = (2i + 2j + 2k)/2√2

C = 5 x (2i + 2j + 2k)/2√2

C = 10i + 10j + 10k/2√2