Question

If a = 2i+3j-4k and b =4i+3j-2k . Find the angle between a and b.​

Answer 1

Explanation:

Hey user;

Formula $\cos(\Theta) = \frac{a.b}{|a| |b|}$

$For \: \\ \\ \vec{a} = 2\hat{i} + 3 \hat{j} - 4 \hat{k} \\ \\ \vec{b} = 4 \hat{i} + 3 \hat{j} - 2 \hat{k}$

$\cos(\Theta) = \frac{ 8 + 9 -8}{\sqrt{4 + 9 +16} \times \sqrt{4 + 9 + 16}} \\ \\ \huge\boxed{ \cos(\Theta) = \frac{ 9}{29}}$