Question

if A=2i+3j+4k and B=4i+3j+2k then ange​

Answer 1

Answer:

Cos⁻¹(25/29)

Explanation:

Cosθ=A.B/|A|×|B|

        = (2)(4)+(3)(3)+(4)(2)/(√(2²+3²+4²))(√(4²+3²+2²))

        = 25/(√29)(√29) = 25/29

Cosθ=25/29⇒θ=Cos⁻¹(25/29)