Question

if A=2i+3j and B=5i+7j then the vector having the magnitude ofA and direction of B would be

Answer 1

magnitude of A = √4+9 = √13

b^ =(5i + 7j)/ √25+49 = (5i+7j)/√74

so √(13/74) ( 5i+7j)

Answer 2

Resultant vector, $R=3.6i+54.46j$

Explanation:

Vector, $A=2i+3j$

Vector, $B=5i+7j$

Magnitude of vector A is,

$|A|=\sqrt{2^2+3^2}$

A = 3.6

Direction of vector B is,

$\theta=tan^{-1}\dfrac{v_y}{v_x}$

$\theta=tan^{-1}\dfrac{7}{5}$

$\theta=54.46^{\circ}$

Let R is the vector having the magnitude of A and direction of B. So,

$R=3.6i+54.46j$

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