If a=2i+3j,b=2j+3k finthe compound of b along a
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Answer:
Explanation:
the component of the vector A along B geometrically is :
Bcos (theta)=(A.B÷/B/). (Bcap)
=5/(2)1/2 (i+j)
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Answer:
bsdk tu sphs se hai kya?
Explanation:
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