Question

If A= 2i+3j, B=2j+3k then the component of "B" vector along "A" vector is The answer should be 6/√13 Plz answer fast. I'll mark as brainliest.

Answer 1

Explanation:

hope you got your answer.

Answer 2

Given:

$A=2i+3j,B=2i+3k$

To find:

The component of "$B$" vector along "$A$" vector.

Explanation:

The component of "$B$" vector along "$A$" vector is, $\| \mathbf{B} \| \cos\theta$.

Then,

$\| \mathbf{B} \| =\sqrt{2^{2}+3^{2} }=\sqrt{4+9}=\sqrt{13}$.

and,

$\cos\theta=\frac{(2i+3j).(2j+3k)}{\| \mathbf{A} \|\| \mathbf{B} \|}$

        $=\frac{6}{\sqrt{13}\sqrt{13} }$

        $=\frac{6}{13}$

Therefore, $\| \mathbf{B} \|\cos\theta=\sqrt{13}\cdot\frac{6}{13} =\frac{6}{\sqrt{13} }$