Physics, asked by shamali4767, 1 year ago

If A = 2i -6j -3k & B = 4i +3j -k find a unit vector perpendicular to the plane of A & B

Answers

Answered by RAXNIGAM
26

Explanation:

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Answered by handgunmaine
19

The unit vector perpendicular to the plane of A & B is :

n=\dfrac{3}{7}i-\dfrac{2}{7}j+\dfrac{6}{7}k

Explanation:

Given that,

Vector, A=2i-6j-3k

Vector, B=4i +3j -k

Let n is the unit vector perpendicular to the plane of A and B. It is given by :

n=\dfrac{A\times B}{|a\times b|}

n=\dfrac{\begin{pmatrix}15&-10&30\end{pmatrix}}{\sqrt{15^2+10^2+30^2}}

n=\dfrac{15i-10j+30k}{35}

So, the unit vector perpendicular to the plane of A & B is :

n=\dfrac{3}{7}i-\dfrac{2}{7}j+\dfrac{6}{7}k

Hence, this is the required solution.

Learn more,

Vectors

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