If a=2n+13 and b=n+7 where not is a natural number then find the hcf of a and b
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Step-by-step explanation:
A=2n+13
B=n+7
on using Euclid's division algorithm,
2n+13= (n+7)(1)+ n+6
as r≠0 applying Euclid's division algorithm,
n+7 = (n+6)(1)+1
as r≠0 applying Euclid's division algorithm,
n+6 = ( 1 )(n+6)+0
as r=0 ,
∴HCF of A and B is 1.
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