If A = 2n + 13, B = n + 7, where n is a natural number, then HCF of A and B is-:
a) 1 b) 2 c)3 d)4
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Given A = 2n + 13 and B = n + 7 and since n is a natural number A > B. Since A/B is not an integer we can conclude that A and B cannot have any integer in common. Therefore HCF of A and B is 1.
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asinx+bcosy=√2sinx
Prove that asinx-bcosy=√2cosy
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