Question

if (a^2sec^2θ)-(b^2tan^2θ) = c^2, Find the value of sinθ

Answer 1

Answer:

((c^2 - a^2)/(c^2 - b^2))^(1/2)

Step-by-step explanation:

See attachment

Answer 2

Pls refer to the pictru for the answer

hope it helps you