if a 2sinA COSB sinc= sinB sin [A +C] , then tan A, tan B and tan c are in
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The given relation is rewritten as
sinBsin(A+C)=2sinAsinCsinB
Divide both sides by sinAsinBsinC
sinAsinC
sin(A+C)
=2cotB
or cotA+cotC=2cotB
Step-by-step explanation:
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