Math, asked by prasannajena566, 9 months ago

If a^2x^2-b^2=0, then x=_____

Answers

Answered by emmaoloyede14
0

Answer:

a^2x^2-b^2=0

=a2 x2−b2=0

Step 1: Add b^2 to both sides.

a2 x2−b2+b2=0+b2

a2 x2=b2

Step 2: Divide both sides by a^2.

a2x2 /a2 = b2 /a2

x2= b2/ a2

Step 3: Take square root.

x=√ b2 /a2

or x = −√ b2 /a2

Answer:

x=√ b2 /a2

or x= −√ b2 /a2

Step-by-step explanation:

Answered by bagkakali
0

Answer:

a^2x^2-b^2= 0

a^2x^2 = b^2

x^2 =b^2 /a^2

x = +b/a , -b/a

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