Math, asked by saswatidas23, 7 months ago

if a^2x-3 b^2x = a^6-x b^5x prove that log (1/3(a+b)) = 1/2 (log a + log b)​

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Answered by anitadoifode01
0

Step-by-step explanation:

a^2x-3 b^2x = a^6-x b^5x prove that log (1/3(a+b)) = 1/2 (log a + log b). answer

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