Question

If A = -(2x + 3), B = -3(x – 2) and C = -2x + 7. Find the value of k if (A + B + C) = kx.

Ans..fast guzz​

Answer 1

Given

➝A = -(2x + 3 )

➝B = -3( x - 2 )

➝C = -2x + 7

➝( A + B + C ) = kx

To Find

➝The Value of k

Now Take

➝( A + B + C ) = kx

Put the value

➝-(2x + 3 ) - 3( x - 2 ) - 2x + 7 = kx

➝-2x - 3 -3x + 6 - 2x + 7 = kx

➝-7x + 10 = kx

➝k = ( -7x + 10)/x

Now Check Our answers , So put the value of k on Given equation

➝-(2x + 3 ) - 3( x - 2 ) - 2x + 7 = kx

➝2x - 3 -3x + 6 - 2x + 7 = (-7x + 10 )/x × x

➝- 7x + 10 = -7x + 10

LHS = RHS

So Value of k is

➝k = (-7x + 10 )/x

Answer 2

Answer:

Given :-

• A = - (2x + 3)
• B = - 3(x - 2)
• C = - 2x + 7
• A + B + C = kx

To Find :-

• What is the value of k.

Solution :-

Given :

• A = - (2x + 3)
• B = - 3(x - 2)
• C = - 2x + 7

Then, according to the question,

⇒ $\sf A + B + C =\: kx$

⇒ $\sf - (2x + 3) - 3(x - 2) - 2x + 7 =\: kx$

⇒ $\sf - 2x - 3 - 3x + 6 - 2x + 7 =\: kx$

⇒ $\sf - 2x - 3x - 2x - 3 + 6 + 7 =\: kx$

⇒ $\sf - 5x - 2x + 3 + 7 =\: kx$

⇒ $\sf - 7x + 10 =\: kx$

➠ $\sf\bold{\red{k =\: \dfrac{- 7x + 10}{x}}}$

$\therefore$ The value of k is $\sf\bold{\dfrac{- 7x + 10}{x}}$.