If A = 2y 2 + 3x – x 2 , B = 3x 2 – y 2 and C = 5x 2 – 3xy then find
(i) A + B (ii) A – B (iii) B + C
(iv) B – C (v) A + B + C (vi) A + B – C
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40
Answer:
Given,
A = 2y² + 3x – x²
B = 3x² – y²
C = 5x² – 3xy
1. A + B = 2y² + 3x – x² + 3x² – y²
= y² + 2x² + 3x
2. A – B = 2y² + 3x – x² - 3x² + y²
= 3y² - 4 x² + 3x
3. B + C = 3x² – y² + 5x² – 3xy
= 8 x² - y² - 3xy
4. B - C = 3x² – y² - 5x² + 3xy
= - 2x² - y² + 3xy
5. A + B + C = 2y² + 3x – x² + 3x² – y² + 5x² – 3xy
= y² + 7x² + 3x - 3 xy
6. A + B - C = 2y² + 3x – x² + 3x² – y² - 5x² + 3xy
= y² - 3x² + 3x + 3 xy
Hope it helps you^_^
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