Question

if A=2y²+3x-x²,B=2x²-3y²,C=3x²-5xy find A+B+C​

Answer 1

Answer:

Step-by-step explanation:

A=2y^2+3x-x^2A=2y2+3x−x2

B=3x^2-y^2B=3x2−y2

C=5x^2-3xyC=5x2−3xy

\text{Now,}Now,

(i)A+B(i)A+B

=2y^2+3x-x^2+3x^2-y^2=2y2+3x−x2+3x2−y2

=2x^2+3x+y^2=2x2+3x+y2

(ii)B+C(ii)B+C

=3x^2-y^2+5x^2-3xy=3x2−y2+5x2−3xy

=8x^2-3xy-y^2=8x2−3xy−y2

(iv)B-C(iv)B−C

=(3x^2-y^2)-(5x^2-3xy)=(3x2−y2)−(5x2−3xy)

=3x^2-y^2-5x^2+3xy=3x2−y2−5x2+3xy

=-2x^2+3xy+y^2=−2x2+3xy+y2

(v)A+B+C(v)A+B+C

=2y^2+3x-x^2+3x^2-y^2+5x^2-3xy=2y2+3x−x2+3x2−y2+5x2−3xy

=7x^2-3xy+y^2+3x=7x2−3xy+y2+3x

(vi)A+B-C(vi)A+B−C

=2y^2+3x-x^2+3x^2-y^2-(5x^2-3xy)=2y2+3x−x2+3x2−y2−(5x2−3xy)

=2y^2+3x-x^2+3x^2-y^2-5x^2+3xy=2y2+3x−x2+3x2−y2−5x2+3xy

=3x^2+3xy+y^2+3x=3x2+3xy+y2+3x

Answer 2

Step-by-step explanation:

A+B+C=2y²+3x-x²+2x²-3y²+3x²-5xy

$= 4 {x}^{2} - {y}^{2} - 5xy + 3x$