Question

if A= 2y²+3x-x²,B= 3x²-y² and C=5x²-3xy then find i) A+B ii) B+C iv) B-C v) A+B +C vi) A+B -C pls find it na ​

Answer 1

$\textbf{Given:}$

$A=2y^2+3x-x^2$

$B=3x^2-y^2$

$C=5x^2-3xy$

$\text{Now,}$

$(i)A+B$

$=2y^2+3x-x^2+3x^2-y^2$

$=2x^2+3x+y^2$

$(ii)B+C$

$=3x^2-y^2+5x^2-3xy$

$=8x^2-3xy-y^2$

$(iv)B-C$

$=(3x^2-y^2)-(5x^2-3xy)$

$=3x^2-y^2-5x^2+3xy$

$=-2x^2+3xy+y^2$

$(v)A+B+C$

$=2y^2+3x-x^2+3x^2-y^2+5x^2-3xy$

$=7x^2-3xy+y^2+3x$

$(vi)A+B-C$

$=2y^2+3x-x^2+3x^2-y^2-(5x^2-3xy)$

$=2y^2+3x-x^2+3x^2-y^2-5x^2+3xy$

$=3x^2+3xy+y^2+3x$

Answer 2

Answer:

\textbf{Given:}Given:

A=2y^2+3x-x^2A=2y2+3x−x2

B=3x^2-y^2B=3x2−y2

C=5x^2-3xyC=5x2−3xy

\text{Now,}Now,

(i)A+B(i)A+B

=2y^2+3x-x^2+3x^2-y^2=2y2+3x−x2+3x2−y2

=2x^2+3x+y^2=2x2+3x+y2

(ii)B+C(ii)B+C

=3x^2-y^2+5x^2-3xy=3x2−y2+5x2−3xy

=8x^2-3xy-y^2=8x2−3xy−y2

(iv)B-C(iv)B−C

=(3x^2-y^2)-(5x^2-3xy)=(3x2−y2)−(5x2−3xy)

=3x^2-y^2-5x^2+3xy=3x2−y2−5x2+3xy

=-2x^2+3xy+y^2=−2x2+3xy+y2

(v)A+B+C(v)A+B+C

=2y^2+3x-x^2+3x^2-y^2+5x^2-3xy=2y2+3x−x2+3x2−y2+5x2−3xy

=7x^2-3xy+y^2+3x=7x2−3xy+y2+3x

(vi)A+B-C(vi)A+B−C

=2y^2+3x-x^2+3x^2-y^2-(5x^2-3xy)=2y2+3x−x2+3x2−y2−(5x2−3xy)

=2y^2+3x-x^2+3x^2-y^2-5x^2+3xy=2y2+3x−x2+3x2−y2−5x2+3xy

=3x^2+3xy+y^2+3x=3x2+3xy+y2+3x

plz give me as brainliest