Question

If A (3,0), B(-3,0) then the locus of the point P is such that PA^2+PB^2=18 is​

Answer 1

Step-by-step explanation:

let P(X, Y)

If A (3,0), B(-3,0) then the locus of the point P is such that PA^2+PB^2=18 is

$({x - 3})^{2} + {y}^{2} + {(x + 3)}^{2} + {y}^{2} = 18$

${x}^{2} - 6x + 9 + {y}^{2} + {x}^{2} + 6x + 9 + {y}^{2} = 18$

$2 {x}^{2} + 2 {y}^{2} = 0$

${x}^{2} + {y}^{2} = 0$