Question

If A = [
3 −1

0 2
] , find matrix B such that A

*A– 2B = 3A + 5I where I is a 2 x 2

identity matrix.

Answer 1

There is ur answer hope it helps

Answer 2

Matrix B is:

$B = [3/2 -5/20 -7/2]$

We begin by computing A * A:

$A * A = [3 -10 2] * [3 -10 2] = [9 -30 4]$

Next, we need to compute 2B and 3A + 5I:

$2B = [2b11 2b122b21 2b22]3A + 5I = [14 -30 11]$

Now we can set up the equation A * A - 2B = 3A + 5I and solve for B:

$[9 -30 4] - [2b11 2b122b21 2b22] = [14 -30 11]$

Simplifying, we get:

$[9 -2b11 -2b12-2b21 4-2b22] = [14 -30 11]$

Equating the corresponding elements, we get the following system of equations:

$9 - 2b11 - 2b12 = 14-2b21 = 04 - 2b22 = 11-2b11 = -3$

Solving this system, we get:

$b11 = 3/2\\b12 = -5/2\\b21 = 0\\b22 = -7/2$

for such more question on matrix

https://brainly.in/question/40405225

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