if a=3^1/2 and b=1^1/4 then prove that a+b=b+a
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Step-by-step explanation:
Given :-
a=3^1/2 and b=1^1/4
To find :-
Prove that a+b=b+a .
Solution :-
Given that
a = 3^1/2
b = 1^1/4
Now
On taking LHS
= a+b
=> (3^1/2) + (1^1/4)
=> √3 + √(√1)
=> √3+√1
=> √3 + 1 ------------------(1)
and
On taking RHS
= b+a
=> (1^1/4)+(3^1/2)
=>√(√1) +√3
=> √ 1 +√3
=> 1 + √3
=> √3+1 ------------------(2)
From (1) & (2)
LHS = RHS
a+b = b+a
Hence, Proved.
Answer:-
a+b = b+a is true for the given problem.
Used formulae:-
If a and b are two real numbers then a+b = b+a is called Commutative property under addition.
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