If a = √3+1
/√3−1
and b = 1
/a , find a2
-b
2 + ab.
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3
Given,.
a = √3+1/ √3-1.
a= 2 + √3
b= 1/a
= √3-1 / √3+1
b= √3 - 2
Now,.
a² -b² +2ab.
= (a-b)(a+b) + 2ab.
>>see picture!!!..
hope it helped you!!!!
a = √3+1/ √3-1.
a= 2 + √3
b= 1/a
= √3-1 / √3+1
b= √3 - 2
Now,.
a² -b² +2ab.
= (a-b)(a+b) + 2ab.
>>see picture!!!..
hope it helped you!!!!
Attachments:
Shubhendu8898:
see picture
i want to ask frm where u take √3-2 in b
by multiplying with congugates ...see second picture
if your answer is √3-2 tjen how u will take it at first how will u assume that only√3-2 is tje answer
bcz it is a congugate of a !!
so i will be easy to solve
sorry i want to ask that u have written that b=1/a = 1/√3+2.
bcz i already solve a=√3+2 so simply i putted it
ok u solved my doubt
pleasure to help you !!
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