Question

if a=√3+1/√3-1 and b=1/a find the value of a^2- b^2 + ab​

Answer 1

Answer:

8$\sqrt{3}$+1

Step-by-step explanation:

by multiplying  and dividing $\sqrt{3}$+1 in a, we get:

($\sqrt{3}$+1)^2/(

=4+2$\sqrt{3}$/3-1 = 4+2

and by multiplying and dividing $\sqrt{3}$-1 in b we get:

($\sqrt{3}$-1)^2/

on simplifying, we get:

2-$\sqrt{3}$=b

now, a^2-b^2= (a+b)(a-b)

=(2+$\sqrt{3}$+2-

=8$\sqrt{3}$

and ab= (2+$\sqrt{3}$)(2-

so answer would be 8$\sqrt{3}$+1

pls mark as the brailiest if u found this answer helpfu

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