Question

if a=√3+1/√3-1 and b=1/a find the value of a²-b²+ab​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

=a=√3+1/√3-1 ,b=√3-1/√3+1

=a^2-b^2+ab

=(√3+1/√3-1)^2-(√3-1/√3+1)^2+a(1/a)

={(√3+1)^4-(√3-1)^4}/(√3-1)^2*(√3+1)^2 +1

={(4+2√3)^2-(4-2√3)^2}/(3-1)^2 +1

={(16+12+16√3)-(16+12-16√3)}/4 +1

=32√3/4 +1

=8√3 +1