if (a+3)+1/(a+3)=4 then the value of (a+3)³+1/(a+3)³ is
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let a+3 =x
x+1/x=4
cube both side
x3 +1/x3+3x(1/x)(x+1/x)=64
x3+ 1/x3 +(x+1/x) =64
put x+1/x=4 in this equation
x+1/x=4
cube both side
x3 +1/x3+3x(1/x)(x+1/x)=64
x3+ 1/x3 +(x+1/x) =64
put x+1/x=4 in this equation
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Answer:
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Step-by-step explanation:
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