Question

If A (3, 1), B(2, 6) and C(-5. 7) are the midpoints of the sides of APQR, then the area of the APQR is:​

Answer 1

Answer:

Ohk

Step-by-step explanation:

Given:

D=(3,1)

E=(2,6)

F=(−5,7)

It is known that if (A

x

,A

y

),(B

x

,B

y

) and (C

x

,C

y

) are the co-ordinates of vertices of a triangle then its area is given as [

2

A

x

(B

y

−C

y

)+B

x

(C

y

−A

y

)+C

x

(A

y

−B

y

)

]

Let A be the area of ΔDEF,

A=

2

1

{3(6−7)+2(7+1)+(−5)(−1−6)}

=

2

1

{3(−1)+2(8)+5(7)}

=

2

1

(−3+16+35)

=24

Area of ΔABC =4× Area of ΔDEF

=4×24

=96 sq. units