Question

If A=3^2-2/3^2+2,B=3^2+2/3^2-2 then A+B is

Answer 1

A = (3²-2)/(3²+2) = (9-2)/(9+2) = 7/11

B = (3²+2)/(3²-2) = (9+2)/(9-2) = 11/7

A+B = 7/11 + 11/7 = (49+121)/77 = 170/77 = 2(16/77)

Answer 2

Answer:

$A+B=\frac{170}{77}$      

Step-by-step explanation:

Given : If $A=\frac{3^2-2}{3^2+2}$ and $B=\frac{3^2+2}{3^2-2}$

To find : A+B ?

Solution :

$A=\frac{3^2-2}{3^2+2}$

Solve,

$A=\frac{9-2}{9+2}$

$A=\frac{7}{11}$

$B=\frac{3^2+2}{3^2-2}$

Solve,

$B=\frac{9+2}{9-2}$

$B=\frac{11}{7}$

Substitute the values,

$A+B=\frac{7}{11}+\frac{11}{7}$

$A+B=\frac{7\times 7+11\times 11}{11\times 7}$

$A+B=\frac{49+121}{77}$

$A+B=\frac{170}{77}$