if a =3+2√2 and b=1\a
find a^4+b^4
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Answered by
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2+2+2=1
a
2
+
b
2
Hope it helps you
+
2
a
b
=
1
Subtracting the second equation from this:
2+2+2−(2+2)=1−2
a
2
+
b
2
+
2
a
b
−
(
a
2
+
b
2
)
=
1
−
2
2=−1
2
a
b
=
−
1
No square that:
422=1
4
a
2
b
2
=
1
222=12
2
a
2
b
2
=
1
2
Squaring 2+2=2
a
2
+
b
2
=
2
4+4+222=4
a
4
+
b
4
+
2
a
2
b
2
=
4
But we already figured out that 222=12
2
a
2
b
2
=
1
2
! So:
4+4+12=4
a
4
+
b
4
+
1
2
=
4
4+4=3.5
a
4
+
b
4
=
3.5
And we have our answer!
a
2
+
b
2
Hope it helps you
+
2
a
b
=
1
Subtracting the second equation from this:
2+2+2−(2+2)=1−2
a
2
+
b
2
+
2
a
b
−
(
a
2
+
b
2
)
=
1
−
2
2=−1
2
a
b
=
−
1
No square that:
422=1
4
a
2
b
2
=
1
222=12
2
a
2
b
2
=
1
2
Squaring 2+2=2
a
2
+
b
2
=
2
4+4+222=4
a
4
+
b
4
+
2
a
2
b
2
=
4
But we already figured out that 222=12
2
a
2
b
2
=
1
2
! So:
4+4+12=4
a
4
+
b
4
+
1
2
=
4
4+4=3.5
a
4
+
b
4
=
3.5
And we have our answer!
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