Math, asked by allstar3, 8 months ago

if a=3+2√2 find the value of a^2-1/a^2​

Answers

Answered by xAnkitax14
2

Answer:

i) a = 3+2√2 ---(1)

ii )1/a = 1/(3+2√2)

Rationalising the denominator,

we get

=(3-2√2)/[(3+2√2)(3-2√2)]

= (3-2√2)/[3²-(2√2)²]

= (3-2√2)/(9-8)

=3-2√2-----(2)

iii ) a+1/a = 3+2√2+3-2√2

= 6 ----(3)

iv) a²+1/a²

= (a+/1a)²-2

= 6²-2

= 36 - 2

= 34

Therefore,

a²+1/a² = 34

OR

a= 1/ 3 -2√2

= 1/3-2√2×3+2√2/ 3+2√2

=6

a+1/a=6

a² -1/a² = (6)²

a² -2.a.1/a +1/a² =36

a² -1/a² = 36-2

a²-1/a²= 34

Step-by-step explanation:

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Answered by MrMovrocker
0
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