Math, asked by madhavendra63, 1 year ago

if a=3-2√2 find the value of a^4-1/a^4​

Answers

Answered by Anonymous
4

Step-by-step explanation:

a + 1/a = (3 - 2√2) + 1/(3 - 2√2)

= (3 - 2√2)² + 1 / (3 - 2√2)

= (9 + 8 - 12√2 + 1)/(3 - 2√2)

= (18 - 12√2) / (3 - 2√2)

= 6(3 - 2√2) / (3 - 2√2)

a + 1/a = 6

a - 1/a = √(a + 1/a)² - 4

= √36 - 4

= √32 = 4√2

(a + 1/a)(a - 1/a) = 6 × 4√2

a² - 1/a² = 24√2 -------(1)

a² + 1/a² + 2 = 36

a² + 1/a² = 34 --------(2)

Now , from equation (1) × (2)

(a² - 1/a²) × (a² + 1/a²) = 24√2 × 34

a⁴ - 1/a⁴ = 816√2

Answered by BrainlyPopularman
4

ANSWER :

a⁴ - 1/a⁴ = - 816√2

EXPLANATION :

GIVEN :

a = 3-2√2

TO FIND :

Value of a⁴ - 1/a⁴.

SOLUTION :

According to the question –

a = 3-2√2

Now let's find 1/a

1/a = [1/(3 - 2√2)][(3 + 2√2)(3 + 2√2)]

1/a = (3 + 2√2)/(9 - 8)

1/a = 3 + 2√2

➨ Now let's find (a² + 1/a²)

(a + 1/a)² = a² + (1/a²) + 2(a)(1/a)

(6)² = a² + (1/a²) + 2

36 = a² + (1/a²) + 2

a² + 1/a² = 34 eq.(1)

➨ Now let's find (a² - 1/a²) –

(a² - 1/a²) = (a - 1/a)(a + 1/a)

a² - 1/a² = (-4√2)(6)

⇨ a² - 1/a² = -24√2 eq.(2)

Now multiply both equations

(a² + 1/a²)(a² - 1/a² ) = a - 1/a

a⁴ - 1/a⁴ = (34)(-24√2)

a⁴ - 1/a⁴ = - 816√2

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