if a=3+2√2 find the value of a²-1
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Given: a = (3 + 2√2)
To Find: Value of (a² - 1).
We know, (a² - b²) = (a + b)(a - b)
also, (x + a)(x + b) = x² + (a + b)x + ab
∴ a² - 1 = [(3 + 2√2) + 1] • [(3 + 2√2) - 1]
⟹ a² - 1 = (3 + 2√2 + 1) • (3 + 2√2 - 1)
⟹ a² - 1 = (2√2 + 4) • (2√2 + 2)
⟹ a² - 1 = (2√2)² + (4 + 2)2√2 + (2)(4)
[∵ (x + a)(x + b) = x² + (a + b)x + ab]
⟹ a² - 1 = 8 + (6)2√2 + 8
⟹ a² - 1 = 16 + 12√2
∴ a² - 1 = 16 + 12√2
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