if a = √3+√2/√3-√2 and b= √3-√2/√3+√2 find a2+b2
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Step-by-step explanation:
a = (√3+√2)/(√3-√2)
By rationalization,
a = (√3+√2)²/[(√3)²-(√2)²]
a = (3+2+2√6)/(3-2)
a = 5+2√6
a² = (5+2√6)²
a² =25+24 +20√6
a² =49+20√6
____________, _
b = (√3-√2)/(√3+√2)
By rationalization,
b = (√3-√2)²/[(√3)² +(√2)²]
b =(3+2-2√6)/(3+2)
b = (5-2√6)/5
b² = [(5-2√6)/5]²
b² = (25+24-20√6)/25
b² = (49-20√6)/25
________
a²+b² = 49+20√6 +(49-20√6)/5
a²+b² = {5(49+20√6) +49-20√6}/5
a²+b² = (245+100√6 +49-20√6)/5
a²+b² = (245+49 +100√6 -20√6)/5
a²+b² = (294+80√6)/5
a²+b² =16√6 +294/5
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