If a= √3-√2/√3+√2 and b= √3+√2/√3-√2. Find the value od a²+b²?
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=(√3-√2)^2/(√3+√2)^2 + (√3+√2)^2/(√3-√2)^2
=5-2√6/5+2√6 + 5+2√6/5-2√6
=98
=5-2√6/5+2√6 + 5+2√6/5-2√6
=98
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