Question

if a = √3-√2/√3+√2 and b = √3+√2/√3-√2 , find the value of a²+b²-5 ab
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Answer 1

Answer:

93

Step-by-step explanation:

A = (√3-√2)/(√3+√2)  = (√3-√2)/(√3+√2)× (√3-√2)/(√3-√2) [ rationalizing it]  =(√3 -√2)²/1 = (√3 -√2)² = 5- 2√6b= (√3+√2)/(√3-√2)×(√3+√2)/(√3+√2) [ rationalizing it] = (√3+√2)²/1 =(√3+√2)² = 5+2√6now, a²+b² - 5ab = (5-2√6)² + (5+2√6)² - 5(5-2√6)(5+2√6)=25 +24 -20√6 +25 +24 + 20√6 - 5(25-24)=98 -5 = 93