Question

If a = 3+√2 , b = 3-√2 then find the value of a square and B square

Answer 1

$a^2+b^2\\ =(3+\sqrt{2})^2+(3-\sqrt{2})^2\\ =9+4+6\sqrt{2}+9+4-6\sqrt{2}\\ =26$

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Answer 2

Step-by-step explanation:

$a = 3 + \sqrt{2} \: \\ b = 3 - \sqrt{2}$

${a}^{2} - {b}^{2} = (a + b)(a - b)$

$=(3 + \sqrt{2} + 3 - \sqrt{2} )(3 + \sqrt{2} - 3 + \sqrt{2} )$

$= 6 \times 2 \sqrt{2}$

$= 12 \sqrt{2}$