Question

if a= 3/2 , b =-7/6 and c= 5 then solve a÷(b÷c)= (a÷b)÷c
plz tell me fast!!!​

Answer 1

Answer:

$\frac{3}{2} \div (\frac{7}{6} \div \frac{5}{1} )= (\frac{3}{2} \div \frac{7}{6}) \div \frac{5}{1}$

$= \frac{3}{2} \div ( \frac{7}{6} \times \frac{1}{5} ) = = (\frac{2}{3} \times \frac{7}{6} ) \div \frac{5}{1}$

$= \frac{3}{2} \div \frac{7}{30} = \frac{14}{18} \div \frac{5}{1}$

$= \frac{3}{2} \times \frac{7}{30} = \frac{14}{18} \times \frac{1}{5}$

$= \frac{21}{60} = \frac{14}{90}$

Now lets bring it into lowest term

$\frac{21}{60} = \frac{7}{20}$

$\frac{14}{90} = \frac{7}{45}$

Therefore ,

a÷(b÷c) is not equal (a÷b)÷c

Hope it helps you

Answer 2

Step-by-step explanation:

LHS

$\frac{3}{2} \div ( \frac{ - 7}{6 } \div 5)$

$\frac{3}{2} \div \frac{-7}{30}$

$\frac{3}{2} \times \frac{-30}{7}$

$\frac{-45}{7}$

RHS

$(\frac{3}{2} \div \frac{-7}{6} ) \div 5$

$( \frac{3}{2} \times \frac{-6}{7} ) \div 5$

$\frac{-9}{7} \times \frac{1}{5}$

-9/35

LHS NOT EQUAL TO RHS