Question

If a = 3 - 2 root 2 b= 1/a , then find the value of a^2 + b^2 + 2ab

Answer 1

$( \sqrt{3 - 2} ) ^{2} + ( \frac{1}{ \sqrt{3 - 2} } ) ^{2} + 2 \times \sqrt{3 - 2} \times \frac{1}{ \sqrt{3 - 2} }$
cut root 2 by squres and root3-2 by root3-2
$3 - 2 + \frac{ {1}^{2} }{3 - 2} + 2 \times 1$
subtract 3-2 as 1
$1 + 1 + 2 = 4$