If a = (√3)/2 then what is the value of √(1 + a) + √(1 – a)
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Step-by-step explanation:
Let us assume P = √1 + a + √1 - a
Square on both side, P 2 = ( √1 + a + √1 - a ) 2
Use the formula ( a + b ) 2 = a 2 + b 2 + 2ab
we will get
⇒ P 2 = (1 + a) + (1- a) + 2 √1 + a x √1 - a⇒ P 2 = (1 + a) + (1- a) + 2 √(1 + a ) x ( 1 - a ) ⇒ P 2 = 2 + 2 √1 - a2⇒ P 2 = 2 (1 + √1 - a2)
Now put the value of a which is given in question;
⇒ P 2 = 2 (1 + √1 - ( √3/2 )2)
⇒ P 2 = 2(1 + √1 - 3/4 )
⇒ P 2 = 2(1 + √1/4 )
⇒ P 2 = 2(1 + 1/2) = 2 x 3/2 = 3
⇒ P= √3∴ (√1 + a + √1 - a) = √3
hope it will help you.........
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