If a^3+3ab^2/3a^b+b^3=x^3+3xy^2/3x^2y+y^3, show that x/a=y/b
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a^3+3ab^2/3a^2b+b^3=x^3+3xy^2/3x^2y+y^3
a(a^2+3b^2)/b(3a^2+b^2)=x(x^2+3y^2)/y(3x^2+y^2) -----(i)
if x/a=y/b
a=xb/y
put the value of a in equation (i)
a/b=x/y
or ay=bx
or x/a=y/b
proved.
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