if A=3/4÷5/6
B=3÷[(4÷5)÷6]
C=[3÷(4÷5)]÷6 and
D=3÷4(5÷6), then
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1
Answer:
A×(B∩C)
∩ Intersection:common between two sets
B∩C={3,4}∩{4,5,6}={4}
A×(B∩C)=
{1,2,3}×{4}
={(1,4),(2,4),(3,4)}
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