If A (3, 4), B (- 2, 3) and C (5, 6) are the vertices of a triangle ABC, find the
length of the median AD from A to BC. Also verify that area of △ABD is equal to
area of △ACD. PLS ANSWER IT PROPERLY...
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AD is the median of ∆ABC.
So, D is the mid-point of BC.
D =
Length of the median AD =
Let A (3, 4), B (-2, 3), and D (1.5, 4.5) be the vertices of the triangle ABD.
By using the formula,Area of triangle, we obtain
Area of ΔABD
But area cannot be negative.
Area of ΔABD = 2
Let A (3, 4), C (5, 6), and D (1.5, 4.5) be the vertices of the triangle ABD.
By using the formula,Area of triangle, we obtain
Area of ΔACD
Area of ΔACD = 2
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