If a=(3/5)^-2÷(7/5)^0,find the value of a ^-3
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Answer:
(3/5)^6
Step-by-step explanation:
a=(3/5)^-2÷(7/5)^0
a=(3/5)^-2×1
a/a
a^-3=(3/5)^(-2×-3)
a^-3=(3/5)^6
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