Math, asked by gyacoobali9948, 11 months ago

If a=(3/5)^-2÷(7/5)^0,find the value of a ^-3

Answers

Answered by Farhan555
3

Answer:

(3/5)^6

Step-by-step explanation:

a=(3/5)^-2÷(7/5)^0

a=(3/5)^-2×1

a/a

a^-3=(3/5)^(-2×-3)

a^-3=(3/5)^6

Similar questions