if a= (3/5)^-2\(7/5)^0, find the value of a^-3
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Step-by-step explanation:
a^0 =1
(x/y)^-b =(y/x)^b
a= (5/3)²/ 1 = (5/3)² =5²/3²
a^-3 = (5²/3²)^-3 = (3²/5²)³= (3/5)^(2×3)=(3/5)⁶
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