Question

if a=3-√5/3+√5 b=3+√5/3-√5 find a^2 -b^2

Answer 1

I think you might satisfy from my answer.

Answer 2

a=3-√5/3+√5
a=3-√5(3-√5)/(3)²-(√5)²
a=9-3√5-3√5+5/9-5
a=14-6√5/4

b=3+√5/3-√5
b=3+√5(3+√5)/(3)²-(√5)²
b=9+3√5+3√5+5/9-5
b=14+6√5/4



a²-b²=(a+b)(a-b)
        =(14-6√5/4+14+6√5/4)(14-6√5/4-14+6√5/4)
        =(14-6√5+14+6√5/4)(14-6√5-14+6√5/4)
        =28/4*0/4
        =7*0
        =0



therefore the value is 0

hope it helps

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